(c) Considering again the combined A
∪Β
system, equilibrium of horizontal and vertical
forces readily yields
H
x
= –
F
x
= 797 N and
H
y
=
Mg
–
F
y
= 931 N. In unitvector notation,
we have
ˆˆ
ˆ
ˆ
i
j
( 797 N)i (931 N)j
xy
HH H
=+=
+
+
G
(d) As mentioned above, Newton’s third law (and the results from part (b)) immediately
provide –
G
x
= – 797 N and –
G
y
= – 265 N for the force components acting on
B
at the
bolt. In unitvector notation, we have
ˆ
ˆ
i
j
( 797 N)i (265 N)j
GGG
−=
− − =−
−
G
38. The phrase “loosely bolted” means that there is no torque exerted by the bolt at that
point (where
A
connects with
B
). The force exerted on
A
at the hinge has
x
and
y
components
F
x
and
F
y
. The force exerted on
A
at the bolt has components
G
x
and
G
y
and
those exerted on
B
are simply –
G
x
and –
G
y
by Newton’s third law. The force exerted on
B
at its hinge has components
H
x
and
H
y
. If a horizontal force is positive, it points
rightward, and if a vertical force is positive it points upward.
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Force

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