(c) Considering again the combined A∪Βsystem, equilibrium of horizontal and vertical forces readily yields Hx= – Fx= 797 N and Hy= Mg– Fy= 931 N. In unit-vector notation, we have ˆˆˆˆij( 797 N)i (931 N)jxyHH H=+=++G(d) As mentioned above, Newton’s third law (and the results from part (b)) immediately provide – Gx= – 797 N and – Gy= – 265 N for the force components acting on Bat the bolt. In unit-vector notation, we have ˆˆij( 797 N)i (265 N)jGGG−=− − =−−G38. The phrase “loosely bolted” means that there is no torque exerted by the bolt at that point (where Aconnects with B). The force exerted on Aat the hinge has xand ycomponents Fxand Fy. The force exerted on Aat the bolt has components Gxand Gyand those exerted on Bare simply –Gxand – Gyby Newton’s third law. The force exerted on Bat its hinge has components Hxand Hy. If a horizontal force is positive, it points rightward, and if a vertical force is positive it points upward.
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