ch12-p046 - 7 N/m 2 ) = 0.0560 J . 46. Since the force is...

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which means the work is (wire-area) × (wire-length) × (graph-area-under-curve). Since the area of a triangle (see the graph in the problem statement) is 1 2 (base)(height) then we determine the work done to be W = (2.00 x 10 6 m 2 )(0.800 m) © § ¹ · 1 2 (1.0 × 10 3 )(7.0 × 10
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Unformatted text preview: 7 N/m 2 ) = 0.0560 J . 46. Since the force is (stress × area) and the displacement is (strain × length), we can write the work integral (eq. 7-32) as W = Fdx ³ = (stress) ³ A (differential strain) L = AL (stress) ³ (differential strain)...
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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