1223825(graph area)(8.0 10m )(8.0 10 m)(4.74 10 N/m )3.03 10 J.KW AL−−−===×××=×(b) The kinetic energy of the fruit fly of mass 6.00 mg and speed 1.70 m/s is 262611(6.00 10kg)(1.70 m/s)8.67 10 J.22fffKmv==×=×(c) Since fKW<, the fruit fly will not be able to break the thread. (d) The kinetic energy of a bumble bee of mass 0.388 g and speed 0.420 m/s is 2425(3.99 10kg)0.420 m/s)3.42 10 J.bbbv=×(e) On the other hand, since b>, the bumble bee will be able to break the thread. 48. Since the force is (stress × area) and the displacement is (strain × length), we can write the work integral (eq. 7-32) as W=Fdx³= (stress)
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.