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cos60
cos20
sin 60
sin 20
TT
TW
T
′
°=
°
′
+
°
horizontal forces
vertical forces.
(a) We solve the above simultaneous equations and find
15N.
tan 60 cos20
sin 20
W
T
==
°°
−°
(b) Also, we obtain
T´
=
T
cos 20º / cos 60º = 29 N.
68. We denote the tension in the upper left string (
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Force

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