ch12-p070 - 70(a The angle between the beam and the floor...

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,max N s F f = 1 μ s = tan θ . Therefore, μ s = 0.35. 70. (a) The angle between the beam and the floor is sin 1 ( d / L )= sin 1 (1.5/2.5) = 37 ° , so that the angle between the beam and the weight vector W of the beam is 53 ° . With L = 2.5 m being the length of beam, and choosing the axis of rotation to be at the base, Σ τ z = 0 ¡ PL W © ¨ § ¹ ¸ · L 2 sin 53 ° = 0 Thus, P = ½ W sin 53 ° = 200 N. (b) Note that P + W = (200 90 ° ) + (500 –127 ° ) = (360 –146 ° ) using magnitude-angle notation (with angles measured relative to the beam, where "uphill" along the beam would correspond to 0
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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