74. (a) Computing the torques about the hinge, we have sin 40sin502LTLW°=°where the length of the beam is L= 12 m and the tension is T= 400 N. Therefore, the weight is 671 NW=, which means that the gravitational force on the beam is ˆ( 671 N)jwF=−G.(b) Equilibrium of horizontal and vertical forces yields, respectively,
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.