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78. (a) For computing torques, we choose the axis to be at support 2 and consider torques
which encourage counterclockwise rotation to be positive. Let
m
= mass of gymnast and
M
= mass of beam. Thus, equilibrium of torques leads to
1
(1.96m)
(0.54m)
(3.92m)=0.
Mg
mg
F
−−
Therefore, the upward force at support 1 is
F
1
= 1163 N (quoting more figures than are
significant — but with an eye toward using this result in the remaining calculation). In
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 Spring '08
 Any
 Physics, Mass

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