ch13-p005 - m A ) solve for r . We find r = 5 d . Thus,...

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5. We require the magnitude of force (given by Eq. 13-1) exerted by particle C on A be equal to that exerted by B on A . Thus, Gm A m C r 2 = Gm A m B d 2 . We substitute in m B = 3 m A and m B = 3 m A , and (after canceling “
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Unformatted text preview: m A ) solve for r . We find r = 5 d . Thus, particle C is placed on the x axis, to left of particle A (so it is at a negative value of x ), at x = 5.00 d ....
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