ch13-p010

# ch13-p010 - (b) We note (from the graph) that the net force...

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10. (a) We are told the value of the force when particle C is removed (that is, as its position x goes to infinity), which is a situation in which any force caused by C vanishes (because Eq. 13-1 has r 2 in the denominator). Thus, this situation only involves the force exerted by A on B : Gm A m B (0.20 m) 2 = 4.17 × 10 10 N . Since m B = 1.0 kg, then this yields m A = 0.25 kg.
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Unformatted text preview: (b) We note (from the graph) that the net force on B is zero when x = 0.40 m. Thus, at that point, the force exerted by C must have the same magnitude (but opposite direction) as the force exerted by A (which is the one discussed in part (a)). Therefore Gm C m B (0.40 m) 2 = 4.17 10 10 N m C = 1.00 kg....
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## This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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