ch13-p010 - (b) We note (from the graph) that the net force...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
10. (a) We are told the value of the force when particle C is removed (that is, as its position x goes to infinity), which is a situation in which any force caused by C vanishes (because Eq. 13-1 has r 2 in the denominator). Thus, this situation only involves the force exerted by A on B : Gm A m B (0.20 m) 2 = 4.17 × 10 10 N . Since m B = 1.0 kg, then this yields m A = 0.25 kg.
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: (b) We note (from the graph) that the net force on B is zero when x = 0.40 m. Thus, at that point, the force exerted by C must have the same magnitude (but opposite direction) as the force exerted by A (which is the one discussed in part (a)). Therefore Gm C m B (0.40 m) 2 = 4.17 10 10 N m C = 1.00 kg....
View Full Document

This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

Ask a homework question - tutors are online