ch13-p013 - 13 If the lead sphere were not hollowed the...

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() 12 22 11 3 2 2 2 2 9 11 1 == =1 8/ 2 8 1 / 2 (6.67 10 m /s kg)(2.95 kg)(0.431 kg) 1 1 ( 9 . 0 01 0m ) 8 [ 1( 41 ) / ( 291 ) ] 8.31 10 N. GMm FFFG M m dd dR Rd −− §· § · ¨¸ ¨ ¸ ¨ ¸ ©¹ © ¹ ×⋅ =− ×− × × 13. If the lead sphere were not hollowed the magnitude of the force it exerts on m would be F 1 = GMm/d 2 . Part of this force is due to material that is removed. We calculate the force exerted on m by a sphere that just fills the cavity, at the position of the cavity, and subtract it from the force of the solid sphere. The cavity has a radius r = R /2. The material that fills it has the same density (mass to
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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