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()
7
total
on
2
3.0 10 N/kg .
m
GmM
Fm
r
−
==
×
(b) At
r
= 0.50 m, the portion of the sphere at radius smaller than that is
33
4
1
.
3
1
0
k
g
.
3
Mr
ρπ
§·
×
¨¸
©¹
Thus, the force on
m
has magnitude
GMm/r
2
=
m
(3.3
×
10
−
7
N/kg).
(c) Pursuing the calculation of part (b) algebraically, we find
3
4
3
7
on
2
N
6.7 10
.
kg m
m
Gm
r
r
r
−
×
⋅
27. Using the fact that the volume of a sphere is 4
π
R
3
/3, we find the density of the sphere:
4
total
3
3
4
4
3
3
1.0 10 kg
2.4 10 kg/m .
1.0 m
M
R
ρ
×
=
×
When the particle of mass
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Mass

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