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32. (a) The potential energy at the surface is (according to the graph) –5.0
×
10
9
J, so
(since
U
is inversely proportional to
r
– see Eq. 1321) at an
r
value a factor of 5/4 times
what it was at the surface then
U
must be a factor of 4/5 what it was.
Thus, at
r
= 1.25
R
s
U
= – 4.0
×
10
9
J.
Since mechanical energy is assumed to be conserved in this problem,
we have
K + U =
–2.0
×
10
9
J at this point.
Since
U
= – 4.0
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 Spring '08
 Any
 Physics, Energy, Potential Energy

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