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(a) For a headon collision, the relative speed of the two objects must be 2
v
= 5.4
×
10
4
km/h.
(b) A perpendicular collision is possible if one satellite is, say, orbiting above the equator
and the other is following a longitudinal line. In this case, the relative speed is given by
the Pythagorean theorem:
22
ν
+
= 3.8
×
10
4
km/h.
44. From Eq. 1337, we obtain
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Mass

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