ch13-p054 - 54. (a) The period is T = 27(3600) = 97200 s,...

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54. (a) The period is T = 27(3600) = 97200 s, and we are asked to assume that the orbit is circular (of radius r = 100000 m). Kepler’s law of periods provides us with an approximation to the asteroid’s mass: () 2 3 21 6 4 (97200) 100000
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