ch13-p056 - 56. The two stars are in circular orbits, not...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
3 35 3 30 2 21 1 3 2 12 (2.7 10 m/s) (1.70 days)(86400 s/day) 6.90 10 kg () 2 2 ( 6 . 6 7 1 0 m / k g s ) 3.467 , s mv T mm G M ππ × == = × = where 30 1.99 10 kg s M is the mass of the sun. With 1 6 s mM = , we write 2 s α = and solve the following cubic equation for : 3 2 3.467 0 (6 ) −= + . The equation has one real solution: 9.3 = , which implies 2 /9 s . 56. The two stars are in circular orbits, not about each other, but about the two-star system’s center of mass (denoted as O ), which lies along the line connecting the centers of the two stars. The gravitational force between the stars provides the centripetal force necessary to keep their orbits circular. Thus, for the visible, Newton’s second law gives
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.
Ask a homework question - tutors are online