76. (a) With 302.0 10 kgM=×and r= 10000 m, we find 12221.310 m/s .gGMar==×(b) Although a close answer may be gotten by using the constant acceleration equations of Chapter 2, we show the more general approach (using energy conservation):
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.