84. See Appendix C. We note that, since v= 2πr/T, the centripetal acceleration may be written as a= 4π2r/T2. To express the result in terms of g, we divide by 9.8 m/s2.(a) The acceleration associated with Earth’s spin (T= 24 h = 86400 s) is 63224(6.3710 m)3.4 10.(86400s) (9.8m/s )aggπ−×==×2(b) The acceleration associated with Earth’s motion around the Sun (
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.