86. We apply the work-energy theorem to the object in question. It starts from a point at the surface of the Earth with zero initial speed and arrives at the center of the Earth with final speed vf. The corresponding increase in its kinetic energy, ½mvf2, is equal to the work done on it by Earth’s gravity: ()FdrKr dr=−³³(using the notation of that Sample Problem referred to in the problem statement). Thus, 002211()fRRmvF drKr drKR
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.