ch13-p100 - 10 9 45 ), where the rectangular components are...

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100. Consider that we are examining the forces on the mass in the lower left-hand corner of the square. Note that the mass in the upper right-hand corner is 20 2 = 28 cm = 0.28 m away. Now, the nearest masses each pull with a force of GmM / r 2 = 3.8 × 10 9 N, one upward and the other rightward. The net force caused by these two forces is (3.8 × 10 9 , 3.8 × 10 9 ) (5.3
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Unformatted text preview: 10 9 45 ), where the rectangular components are shown first -- and then the polar components (magnitude-angle notation). Now, the mass in the upper right-hand corner also pulls at 45 , so its force-magnitude (1.9 10 9 ) will simply add to the magnitude just calculated. Thus, the final result is 7.2 10 9 N....
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