ch44-p039 - 39. (a) From Eq. 41-29, we know that N 2 N1 = e...

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() 5 1 2 4 1 0.25 ln 8.62 10 eV K 2.7K ln 0.25 2.56 10 eV 0.26 meV. N Ek T N ⎛⎞ ∆= = × ⎜⎟ ⎝⎠ (b) Using 1240eV nm, hc =⋅ we get 6 4 1240eV nm 4.84 10 nm 4.8mm. 2.56 10 eV
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