ch43-p013 - 13(a If X represents the unknown fragment then...

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13. (a) If X represents the unknown fragment, then the reaction can be written 92 235 Un G e +→ + 0 1 32 82 Z A X where A is the mass number and Z is the atomic number of the fragment. Conservation of charge yields 92 + 0 = 32 + Z , so Z = 60. Conservation of mass number yields 235 + 1 = 83 + A , so A = 153. Looking in Appendix F or G for nuclides with Z = 60, we find that the unknown fragment is 60 153 Nd. (b) We neglect the small kinetic energy and momentum carried by the neutron that triggers the fission event. Then, Q = K Ge + K Nd , where K Ge is the kinetic energy of the germanium nucleus and K Nd is the kinetic energy of the neodymium nucleus. Conservation of momentum yields G G pp Ge Nd + = 0. Now, we can write the classical formula for kinetic energy in terms of the magnitude of the momentum
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