13. (a) If X represents the unknown fragment, then the reaction can be written
92
235
Un
G
e
+→
+
0
1
32
82
Z
A
X
where
A
is the mass number and
Z
is the atomic number of the fragment. Conservation of
charge yields 92 + 0 = 32 +
Z
, so
Z
= 60. Conservation of mass number yields 235 + 1 =
83 +
A
, so
A
= 153. Looking in Appendix F or G for nuclides with
Z
= 60, we find that
the unknown fragment is
60
153
Nd.
(b) We neglect the small kinetic energy and momentum carried by the neutron that
triggers the fission event. Then,
Q = K
Ge
+
K
Nd
,
where
K
Ge
is the kinetic energy of the germanium nucleus and
K
Nd
is the kinetic energy of
the neodymium nucleus. Conservation of momentum yields
G
G
pp
Ge
Nd
+
=
0. Now, we can
write the classical formula for kinetic energy in terms of the magnitude of the momentum
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 Spring '08
 Any
 Physics, Charge, Mass

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