ch43-p030 - 30. We are given the energy release per fusion...

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t = × 79 10 100 7 9 10 2 5 10 13 11 4 . .. J W sy . 30. We are given the energy release per fusion ( Q = 3.27 MeV = 5.24 × 10 – 13 J) and that a pair of deuterium atoms are consumed in each fusion event. To find how many pairs of deuterium atoms are in the sample, we adapt Eq. 42-21:
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This note was uploaded on 05/19/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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