ch43-p035 - ∆ M = ( dM / dt ) ∆ t = (4.33 × 10 9 kg/s)...

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35. (a) Let M be the mass of the Sun at time t and E be the energy radiated to that time. Then, the power output is P = dE / dt = ( dM / dt ) c 2 , where E = Mc 2 is used. At the present time, () 26 9 2 2 8 3.9 10 W 4 . 31 0k gs . 2.998 10 m s dM P dt c × ==
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Unformatted text preview: ∆ M = ( dM / dt ) ∆ t = (4.33 × 10 9 kg/s) (4.5 × 10 9 y) (3.156 × 10 7 s/y) = 6.15 × 10 26 kg. The fraction lost is 26 4 30 26 6.15 10 kg 3.1 10 . 2.0 10 kg 6.15 10 kg M M M − ∆ × = = × + ∆ × + ×...
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This note was uploaded on 05/19/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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