ch43-p042 - 42. (a) We are given the energy release per...

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42. (a) We are given the energy release per fusion (calculated in §43-7: Q = 26.7 MeV = 4.28 × 10 – 12 J) and that four protons are consumed in each fusion event. To find how many sets of four protons are in the sample, we adapt Eq. 42-21: () 23 26 sam 4A 1000g 6.02 10 mol 1.5 10 . 44 1 . 0 g m o l p H M NN M ⎛⎞ == ×= × ⎜⎟ ⎝⎠ Multiplying this by Q gives the total energy released: 6.4 × 10 14 J. It is not required that the answer be in SI units; we could have used MeV throughout (in which case the answer is 4.0 × 10 27 MeV).
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This note was uploaded on 05/19/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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