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49. Since 1.00 L of water has a mass of 1.00 kg, the mass of the heavy water in 1.00 L is
0.0150
×
10
– 2
kg = 1.50
×
10
– 4
kg. Since a heavy water molecule contains one oxygen
atom, one hydrogen atom and one deuterium atom, its mass is
(16.0 u + 1.00 u + 2.00 u) = 19.0 u = (19.0 u)(1.661
×
10
– 27
kg/u) = 3.16
×
10
– 26
kg.
The number of heavy water molecules in a liter of water is
(1.50
×
10
– 4
kg)/(3.16
×
10
– 26
kg) = 4.75
×
10
21
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 Spring '08
 Any
 Physics, Mass

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