n17.59MeV3.541MeV1 (/)1 (4.0015u/1.008665u)QKmmα===++where we have found the mass of the alpha particle by subtracting two electron masses from the 4He mass (quoted several times in this and the previous chapter). (b) Then, Kn= Q – Kyields 14.05 MeV for the neutron kinetic energy. 50. Conservation of energy gives Q = K+ Kn, and conservation of linear momentum (due to the assumption of negligible initial velocities) gives |
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This note was uploaded on 05/19/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.