51. (a) From ρH= 0.35= npmp, we get the proton number density np: ()( )53313270.35 1.5 10 kg m0.353.1 10 m .1.67 10kgppnm−−×===××(b) From Chapter 19 (see Eq. 19-9), we have NVpkT××=×−−101 10138 10273268 10
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This note was uploaded on 05/19/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.