ch43-p054

# ch43-p054 - 54(a Rather than use P(v as it is written in Eq...

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Km v m kT m kT vp p , == F H G I K J = 1 2 1 2 2 2 2 which is twice as large as that found in part (a). Thus, at T = 1.5 × 10 7 K we have K v,p = 1.3 keV, which is indicated in Fig. 43-10 by a single vertical line. 54. (a) Rather than use P ( v ) as it is written in Eq. 19-27, we use the more convenient nK expression given in Problem 43-32. The n ( K ) expression can be derived from Eq. 19-27, but we do not show that derivation here. To find the most probable energy, we take the derivative of n ( K ) and set the result equal to zero: dn K dK n kT K K kT e KK KkT p p () . , // / / = = =− F H G I K J = 113 1 2 0 32 12 which gives Kk T p = 1 2 . Specifically, for T = 1.5 × 10 7 K we find
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## This note was uploaded on 05/19/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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