ch43-p056

# Ch43-p056 - 56 First we figure out the mass of U-235 in the sample(assuming 3.0 refers to the proportion by weight as opposed to proportion by

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56. First, we figure out the mass of U-235 in the sample (assuming “3.0%” refers to the proportion by weight as opposed to proportion by number of atoms): 238 235 U 235 sam 238 235 16 (97%) (3.0%) (3.0%) (97%) (3.0%) 2 0.97(238) 0.030(235) (0.030)(1000 g) 0.97(238) 0.030(235) 2(16.0) 26.4 g. mm MM m ⎛⎞ + = ⎜⎟ ++ ⎝⎠ + = = Next, this uses some of the ideas illustrated in Sample Problem 42-5; our notation is similar to that used in that example. The number of 235 U nuclei is N 235 22 26 4 235 677 10 = × (. / .. g)(6.02 10 mol) g/mol 23 If all the U-235 nuclei fission, the energy release (using the result of Eq. 43-6) is
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## This note was uploaded on 05/19/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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