Ch43-p056 - 56 First we figure out the mass of U-235 in the sample(assuming 3.0 refers to the proportion by weight as opposed to proportion by

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
56. First, we figure out the mass of U-235 in the sample (assuming “3.0%” refers to the proportion by weight as opposed to proportion by number of atoms): 238 235 U 235 sam 238 235 16 (97%) (3.0%) (3.0%) (97%) (3.0%) 2 0.97(238) 0.030(235) (0.030)(1000 g) 0.97(238) 0.030(235) 2(16.0) 26.4 g. mm MM m ⎛⎞ + = ⎜⎟ ++ ⎝⎠ + = = Next, this uses some of the ideas illustrated in Sample Problem 42-5; our notation is similar to that used in that example. The number of 235 U nuclei is N 235 22 26 4 235 677 10 = × (. / .. g)(6.02 10 mol) g/mol 23 If all the U-235 nuclei fission, the energy release (using the result of Eq. 43-6) is
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 05/19/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

Ask a homework question - tutors are online