ch42-p015 - 15. Let f24 be the abundance of 24Mg, let f25...

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15. Let f 24 be the abundance of 24 Mg, let f 25 be the abundance of 25 Mg, and let f 26 be the abundance of 26 Mg. Then, the entry in the periodic table for Mg is 24.312 = 23.98504 f 24 + 24.98584 f 25 + 25.98259 f 26 . Since there are only three isotopes, f f f 24 25 26 1 + + = . We solve for f 25 and f 26 . The second equation gives f f f 26 24 25 1 =− − . We substitute this expression and f 24
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This note was uploaded on 05/19/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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