ch42-p016 - 16. (a) The first step is to add energy to...

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() ( ) 314 2 1 HHH e 3.01605u+1.00783u 4.00260u 931.5MeV/u 19.8MeV. Emmmc ∆= + − = = (b) The second step is to add energy to produce 3 HH . + n 2 The energy needed is ( ) 23 2 2 2.01410u+1.00867u 3.01605u 931.5MeV/u 6.26MeV. n Emm m c = = (c) The third step: 2 H →+ pn , which — to make the electrons “balance” — may be rewritten as 2 + 1 n . The work required is ( )( ) 12 2 3 1.00783u 1.00867u 2.01410u 931.5MeV/u 2.23MeV. n m c = + = (d) The total binding energy is be 1 2 3 EE E E + + = 19.8MeV 6.26MeV
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