ch42-p018 - 18. From Appendix F and/or G, we find Z = 107...

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18. From Appendix F and/or G, we find Z = 107 for Bohrium, so this isotope has N = A – Z = 262 – 107 = 155 neutrons. Thus, () ( ) ( ) 2 HB h ben 107 1.007825u
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This note was uploaded on 05/19/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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