ch42-p035 - 35. (a) We assume that the chlorine in the...

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35. (a) We assume that the chlorine in the sample had the naturally occurring isotopic mixture, so the average mass number was 35.453, as given in Appendix F. Then, the mass of 226 Ra was m = + 226 226 2 35 010 761 10 3 .453 .. af gg . The mass of a 226 Ra nucleus is (226 u)(1.661 × 10 – 24 g/u) = 3.75 × 10 – 22 g, so the number of 226 Ra nuclei present was N = (76.1 × 10 – 3
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