(0.3466/s)(173)60/s60 BqRNλ==≈=. 36. The number of atoms present initially at 0t=is 602.00 10N=×. From Fig. 42-19, we see that the number is halved at 2.00 s.t=Thus, using Eq. 42-15, we find the decay constant to be 1000111lnlnln 20.3466 s2.00 s/ 22.00 s
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This note was uploaded on 05/19/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.