ch42-p036 - 36. The number of atoms present initially at t...

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(0.3466/s)(173) 60/s 60 Bq RN λ == = . 36. The number of atoms present initially at 0 t = is 6 0 2.00 10 N . From Fig. 42-19, we see that the number is halved at 2.00 s. t = Thus, using Eq. 42-15, we find the decay constant to be 1 00 0 11 1 ln ln ln 2 0.3466 s 2.00 s / 2 2.00 s
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