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−
−
−
=
1
0
λ
λ
λ
ln
.
R
N
RN
t
We solve for
N
:
N
R
N
R
e
t
=+ −
F
H
I
K
−
λλ
λ
0
.
After many halflives, the exponential is small and the second term can be neglected.
Then,
N = R
/
λ
, regardless of the initial value
N
0
. At times that are long compared to the
halflife, the rate of production equals the rate of decay and
N
is a constant.
43. If
N
is the number of undecayed nuclei present at time
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This note was uploaded on 05/19/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Light

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