∆Emmmcmmmcmmmccmmmmcnp2222238 050792 1008672 100783234 043639315241=−−+−−+−−−−−−−238237237236236235235234238234UUUPaPaPaPaThUThuuuuMeV/uMeV.didiafafaf....(c) This leads us to conclude that the binding energy of the αparticle is 2412832mc=−−=HeMeV 4.25MeVMeV.48. (a) The nuclear reaction is written as 2384h+He.→234The energy released is ∆c12238 05079425=−−−=UHeThu4.00260 u 234.04363u
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This note was uploaded on 05/19/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.