ch42-p054 - 54. (a) We recall that mc2 = 0.511 MeV from...

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54. (a) We recall that mc 2 = 0.511 MeV from Table 37-3, and hc = 1240 MeV·fm. Using Eq. 37-54 and Eq. 38-13, we obtain λ == + = + h p hc KK m c 22 2 2 2 1240 10 2 10 0511 90 10 MeV fm MeV MeV MeV fm. .. . . b g b gb g (b) r = r 0 A 1/3 = (1.2 fm)(150) 1/3 = 6.4 fm. (c) Since >> r the electron cannot be confined in the nuclide. We recall that at least λ /2 was needed in any particular direction, to support a standing wave in an “infinite well.” A
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This note was uploaded on 05/19/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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