ch42-p057 - 57(a Since the positron has the same mass as an...

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57. (a) Since the positron has the same mass as an electron, and the neutrino has negligible mass, then mc m c e 22 =+ mm BC bg . Now, since Carbon has 6 electrons (see Appendix F and/or G) and Boron has 5 electrons, we can add and subtract 6 m e to the above expression and obtain m m c m m e ee 2 76 2 = +− =+− B C di We note that our final expression for mc 2 involves the atomic masses, as well an “extra”
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This note was uploaded on 05/19/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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