ch42-p073

ch42-p073 - 73. A generalized formation reaction can be...

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where m X , m x , and m Y are masses, K x and K Y are kinetic energies, and E Y is the excitation energy of Y. Conservation of momentum yields pp xY = . Now, 2 2 22 xx Y Yx YYY pm p KK mmm ⎛⎞ === ⎜⎟ ⎝⎠ so mc mc K mc m m K E Xxx Y x Y x Y 2 ++ =+ + / bg and K m mm m cE x Y YXx Y = −− + 2 (a) Let x represent the alpha particle and X represent the 16 O nucleus. Then, ( m Y – m X – m x ) c 2 = (19.99244 u –15.99491 u – 4.00260 u)(931.5 MeV/u) = – 4.722 MeV and () 19.99244u 4.722MeV+25.0MeV 25.35MeV 25.4 MeV. 19.99244u 4.00260u K α =− = (b) Let x represent the proton and X represent the 19 F nucleus. Then, ( m Y – m X m x ) c 2 = (19.99244 u –18.99841 u –1.00783 u)(931.5 MeV/u) = – 12.85 MeV and K = −= 19 99244 19 99244 100783 12 85 12 80 . .. u uu MeV +25.0MeV MeV. (c) Let x represent the photon and X represent the 20 Ne nucleus. Since the mass of the photon is zero, we must rewrite the conservation of energy equation: if E γ is the energy of the photon, then E + m X c 2 = m Y c 2 + K Y + E Y . 73. A generalized formation reaction can be written X+x Y, where X is the target

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ch42-p073 - 73. A generalized formation reaction can be...

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