Ch42-p080 - 80 Let N AA0 be the number of element AA at t = 0 At a later time t due to radioactive decay we have N AA0 = N AA N BB N CC The decay

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
1/2 ln 2 ln 2 0.0866/ d 8.00 d T λ == = . Since BB CC /2 NN = , when CC AA /1 . 5 0 = , BB AA /3 . 0 0 = . Therefore, at time t , AA0 AA BB CC AA AA AA AA 3.00 1.50 5.50 N N N N N N =++=+ + = . Since AA AA0 t e = , combining the two expressions leads to AA0 AA 5.50 t N e N which can be solved to give ln(5.50) ln(5.50) 19.7 d 0.0866/ d
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 05/19/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

Ask a homework question - tutors are online