ch41-p003 - 3. (a) Eq. 41-5 gives N (E) = 8 2m3 / 2 1/ 2 E...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
() // Js m J s J m 22 33 / 2 ⋅⋅ = −− 32 3 3 . This means C × = × (. ) . . / 1062 10 1602 10 681 10 56 3 19 27 3 3 2 Jm J / e V ) m e V 3/2 (c) If E = 5.00 eV, then 27 3 3/2 1/2 28 1 3 ( ) (6.81 10 m eV )(5.00eV) 1.52 10 eV m . NE = × 3. (a) Eq. 41-5 gives 3 82 m E h π = for the density of states associated with the conduction electrons of a metal. This can be written NE CE = where 31 3/2 56 3/2 3 3 4 3 8 2 8 2 (9.109 10
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.
Ask a homework question - tutors are online