This preview shows page 1. Sign up to view the full content.
6. Let
E
1
= 63 meV +
E
F
and
E
2
= – 63 meV +
E
F
. Then according to Eq. 416,
P
ee
EE k
T
x
F
1
1
1
1
1
1
=
+
=
+
−
()
/
where
xE
E
k
T
F
=−
/
1
. We solve for
e
x
:
e
P
x
=
−
=
1
1
1
0 090
1
91
9
1
.
.
Thus,
21
2
/
/
1
11
1
1
0.91,
1
(
9
1
/
9
)
1
FF
T
T
x
P
e
−−
−
This is the end of the preview. Sign up
to
access the rest of the document.
 Spring '08
 Any
 Physics

Click to edit the document details