13. (a) We evaluate
P
(
E
) =
(
)
1/(
1)
F
EE k
T
e
−
+
for the given value of
E
, using
kT
=
×
×
=
−
−
(.
.
..
1381 10
1602 10
0 02353
23
19
J / K)(273K)
J/eV
eV
For
E
= 4.4 eV, (
E –
E
F
)/
kT
= (4.4 eV –
5.5 eV)/(0.02353 eV) = – 46.25 and
46.25
1
()
1
.
0
.
1
PE
e
−
==
+
(b) Similarly, for
E
= 5.4 eV,
P
(
E
) = 0.986
0.99
≈
.
(c) For
E
= 5.5 eV,
P
(
E
) = 0.50.
(d) For
E
= 5.6 eV,
P
(
E
) = 0.014.
(e) For
E
= 6.4 eV,
P
(
E
) = 2.447
×
10
– 17
≈
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This note was uploaded on 05/19/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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