ch41-p024 - 24. The probability that a state with energy E...

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5 1.10eV 8.51 (8.62 10 eV / K)(1500K) F EE kT == × , so 4 8.51 1 ( ) 2.01 10 . 1 PE e × + From Fig. 41-6, we find the density of states at 6.0 eV to be about 28 3 () 1 . 71 0/m e V . NE Thus, using Eq. 41-7, the density of occupied states is 28 3 4 24 3 O ( ) ( ) ( ) (1.7 10 / m eV)(2.01 10 ) 3.42 10 / m eV. NE NEPE = = ×⋅ × = Within energy range of 0.0300 eV E ∆= and a volume 83 5.00 10 m , V the number of occupied states is 24 3 8 3 O 15 number ( )
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This note was uploaded on 05/19/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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