Ch41-p026 - 26 From Eq 41-9 we find the number of conduction electrons per unit volume to be 16 2 me EF n= 3 h2 16 2(me c 2 EF = 3(hc 2 = 50.9 nm3

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
3/2 2 6 22 2 32 8 3 43 () 16 2 16 2 16 2 (0.511 10 eV)(5.0 eV) 3 3 ( ) 3 (1240 eV nm) 50.9/ nm 5.09 10 /m 8.4 10 mol/m . eF e F mE mc E n hh c ππ π ⎛⎞ × == = ⎜⎟ ⎝⎠ × ≈× Since the atom is bivalent, the number density of the atom is atom / 2 4.2 10 mol/m . nn × Thus, the mass density of the atom is
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 05/19/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

Ask a homework question - tutors are online