ch41-p032 - 32. (a) The number of electrons in the valence...

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NN P E N e cc c EE k T c ec F == + bg 1 , Hence, from N ev = N hc , we get N e N e v T c T vc −− + = + FF 11 . (b) In this case, F () 1 c T e >> and e T v F 1 . Thus, from the result of part (a), , EE cF vF cv kT kT ee or ( ) 2 vc F EE E k T eN N −+ . We solve for E F : ln . 22 c v Fv c N E k T N ⎛⎞ ≈+ + ⎜⎟ ⎝⎠ 32. (a) The number of electrons in the valence band is P E N e vv v T v ev F + 1 . Since there are a total of N v states in the valence band, the number of holes in the valence
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This note was uploaded on 05/19/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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