ch41-p036 - 15 m 3 )] = 5 10 5 . Here the factor of 2 in...

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36. (a) n -type, since each phosphorus atom has one more valence electron than a silicon atom. (b) The added charge carrier density is n P = 10 – 7 n Si = 10 – 7 (5 × 10 28 m – 3 ) = 5 × 10 21 m – 3 . (c) The ratio is (5 × 10 21 m – 3 )/[2(5 × 10
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Unformatted text preview: 15 m 3 )] = 5 10 5 . Here the factor of 2 in the denominator reflects the contribution to the charge carrier density from both the electrons in the conduction band and the holes in the valence band....
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