ch41-p037

# ch41-p037 - 37. Sample Problem 41-6 gives the fraction of...

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According to Sample Problem 41-6 one of every 5 × 10 6 silicon atoms is replaced with a phosphorus atom. This means there will be P N = (2.14 × 10 22 )/(5 × 10 6 ) = 4.29 × 10 15 phosphorus atoms in 1.0 g of silicon. The molar mass of phosphorus is P M = 30.9758 g/mol so the mass of a phosphorus atom is 0,P P / A mM N == (30.9758 g/mol)/(6.022 × 10 – 23 mol – 1 ) = 5.14 × 10 – 23 g. The mass of phosphorus that must be added to 1.0 g of silicon is PP 0 , P mN m (4.29 × 10 15 )(5.14 × 10 – 23 g) = 2.2 × 10 – 7 g. 37. Sample Problem 41-6 gives the fraction of silicon atoms that must be replaced by
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## This note was uploaded on 05/19/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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