ch41-p039 - N = (662 10 3 eV)/(1.1 eV) = 6.0 10 5 . Since...

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39. The energy received by each electron is exactly the difference in energy between the bottom of the conduction band and the top of the valence band (1.1 eV). The number of electrons that can be excited across the gap by a single 662-keV photon is
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Unformatted text preview: N = (662 10 3 eV)/(1.1 eV) = 6.0 10 5 . Since each electron that jumps the gap leaves a hole behind, this is also the number of electron-hole pairs that can be created....
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This note was uploaded on 05/19/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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