# HW2 - PROBLEM 2.21 Determine lhc x and 71‘ components...

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Unformatted text preview: PROBLEM 2.21 Determine lhc x and 71‘ components ufench ofthc forces shown. SOLUTION ‘ .m k:\" Fara? F : +(20 kmcosmﬁ F‘ =15.32kN 4 Fl. = +(20 kN)sin40°, {A} :12,86k1\' 4 30 km" HH'(‘€.' F‘ : 7(30kN}c05701 F}. = 710.25 W 4 F1. : + (30 kN]sin 70-: P}. 43 1d." Fm‘t'r." I“ = ,{42 kN)c032(P. \. F] : + (42 kN)sinZU”. r} = 14.36 W 4 ilmi: Imu :\ _ m 3 N um PROBLEM 2.24 Determine the .r and 71' components ol‘each of'thc forces H‘hOWH. ‘J .. m4 SOLUTION We compute the lbllowing distances: ?‘ .— 7 — — i ' 2.0_ H 0.4 : V170) +(240)' : 250 mm TF\‘—“L F_ _7 Y 1|. "' 7' /""T ()5 =- View)" 4 (200) : 290 mm \ f 1 - :4c ; VIE-OCH / ‘ ﬁ_i__ } \I A“ i I ()(' : 311204)" 4225}’ = 2<in1m **['—‘J*_* 3 ,‘Iﬂﬂﬁ’f‘m‘r‘r: M | , ‘ | ‘ - ,' 7f) CA- 1-1.: inﬂﬂNt- i F‘ : 7140.0 N4 T 250) | 4 - , '24)‘- X; + 1L, : +5001~ﬂ7L F 7 480N d ._. __ xrriﬁ _,, k ‘ Hie-*1! " 435 N Furry: '—'-;_ quEN‘h-Qué. I'M er ‘ , , 6210‘ , _ I“. 43ml _] F\:313N4 290, -’2 0" F : F435M -04 +1: 3onN< ‘ 3290, 5 i (I N Font): _ (I 0“ L —+ol()N‘ — F\=240N4 ‘255 ' 2 5 H = —5|0N| —27 1" ; 745w 4 PROBLEM 2.41 Boom .48 is held in lllc position shown by three cables. Knowingr that the ( . . _ . l‘ m.‘ “'l tensmm 1n cablcs :H' and .41.) are 4 kN and 3.2 kN. respectively. I determine (a) the tension in cable AL" if thc resultant of the tensions ‘1] cxertcd at point .71 of the boom nnm be directed allow:' .48. l3 _ (h) thc corresponding magnitude ofthc rcsnllnnt. .\ - , \‘“ 30/ P _t SOLUTION 26° amen / ggo Fl Choose _\‘-axis along bar .48. Then (a) Require R. = 2F. -— l): [4kNlc0525° + {5.2 kN )sinBS” 7 TN sinbiC U 01' T,,_ : 7.2909 kN T”. : 7.29 kN 4 (b) R = 2F. : -(4 kmssz“ 7 (5.2 kN lc0535“’ (7.2909 kN‘1cnso5” : —9.[)3 RX lRl : 9.03 RN 4 ...
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HW2 - PROBLEM 2.21 Determine lhc x and 71‘ components...

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